3.19 \(\int \frac {1}{(c+d x) (a+i a \cot (e+f x))} \, dx\)

Optimal. Leaf size=161 \[ -\frac {i \text {Ci}\left (2 x f+\frac {2 c f}{d}\right ) \sin \left (2 e-\frac {2 c f}{d}\right )}{2 a d}-\frac {\text {Ci}\left (2 x f+\frac {2 c f}{d}\right ) \cos \left (2 e-\frac {2 c f}{d}\right )}{2 a d}+\frac {\sin \left (2 e-\frac {2 c f}{d}\right ) \text {Si}\left (2 x f+\frac {2 c f}{d}\right )}{2 a d}-\frac {i \cos \left (2 e-\frac {2 c f}{d}\right ) \text {Si}\left (2 x f+\frac {2 c f}{d}\right )}{2 a d}+\frac {\log (c+d x)}{2 a d} \]

[Out]

-1/2*Ci(2*c*f/d+2*f*x)*cos(-2*e+2*c*f/d)/a/d+1/2*ln(d*x+c)/a/d-1/2*I*cos(-2*e+2*c*f/d)*Si(2*c*f/d+2*f*x)/a/d+1
/2*I*Ci(2*c*f/d+2*f*x)*sin(-2*e+2*c*f/d)/a/d-1/2*Si(2*c*f/d+2*f*x)*sin(-2*e+2*c*f/d)/a/d

________________________________________________________________________________________

Rubi [A]  time = 0.28, antiderivative size = 161, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.174, Rules used = {3726, 3303, 3299, 3302} \[ -\frac {i \text {CosIntegral}\left (\frac {2 c f}{d}+2 f x\right ) \sin \left (2 e-\frac {2 c f}{d}\right )}{2 a d}-\frac {\text {CosIntegral}\left (\frac {2 c f}{d}+2 f x\right ) \cos \left (2 e-\frac {2 c f}{d}\right )}{2 a d}+\frac {\sin \left (2 e-\frac {2 c f}{d}\right ) \text {Si}\left (2 x f+\frac {2 c f}{d}\right )}{2 a d}-\frac {i \cos \left (2 e-\frac {2 c f}{d}\right ) \text {Si}\left (2 x f+\frac {2 c f}{d}\right )}{2 a d}+\frac {\log (c+d x)}{2 a d} \]

Antiderivative was successfully verified.

[In]

Int[1/((c + d*x)*(a + I*a*Cot[e + f*x])),x]

[Out]

-(Cos[2*e - (2*c*f)/d]*CosIntegral[(2*c*f)/d + 2*f*x])/(2*a*d) + Log[c + d*x]/(2*a*d) - ((I/2)*CosIntegral[(2*
c*f)/d + 2*f*x]*Sin[2*e - (2*c*f)/d])/(a*d) - ((I/2)*Cos[2*e - (2*c*f)/d]*SinIntegral[(2*c*f)/d + 2*f*x])/(a*d
) + (Sin[2*e - (2*c*f)/d]*SinIntegral[(2*c*f)/d + 2*f*x])/(2*a*d)

Rule 3299

Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[SinIntegral[e + f*x]/d, x] /; FreeQ[{c, d,
e, f}, x] && EqQ[d*e - c*f, 0]

Rule 3302

Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[CosIntegral[e - Pi/2 + f*x]/d, x] /; FreeQ
[{c, d, e, f}, x] && EqQ[d*(e - Pi/2) - c*f, 0]

Rule 3303

Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Dist[Cos[(d*e - c*f)/d], Int[Sin[(c*f)/d + f*x]
/(c + d*x), x], x] + Dist[Sin[(d*e - c*f)/d], Int[Cos[(c*f)/d + f*x]/(c + d*x), x], x] /; FreeQ[{c, d, e, f},
x] && NeQ[d*e - c*f, 0]

Rule 3726

Int[1/(((c_.) + (d_.)*(x_))*((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)])), x_Symbol] :> Simp[Log[c + d*x]/(2*a*d), x
] + (Dist[1/(2*a), Int[Cos[2*e + 2*f*x]/(c + d*x), x], x] + Dist[1/(2*b), Int[Sin[2*e + 2*f*x]/(c + d*x), x],
x]) /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[a^2 + b^2, 0]

Rubi steps

\begin {align*} \int \frac {1}{(c+d x) (a+i a \cot (e+f x))} \, dx &=\frac {\log (c+d x)}{2 a d}+\frac {i \int \frac {\sin \left (2 \left (e+\frac {\pi }{2}\right )+2 f x\right )}{c+d x} \, dx}{2 a}+\frac {\int \frac {\cos \left (2 \left (e+\frac {\pi }{2}\right )+2 f x\right )}{c+d x} \, dx}{2 a}\\ &=\frac {\log (c+d x)}{2 a d}-\frac {\left (i \cos \left (2 e-\frac {2 c f}{d}\right )\right ) \int \frac {\sin \left (\frac {2 c f}{d}+2 f x\right )}{c+d x} \, dx}{2 a}-\frac {\cos \left (2 e-\frac {2 c f}{d}\right ) \int \frac {\cos \left (\frac {2 c f}{d}+2 f x\right )}{c+d x} \, dx}{2 a}-\frac {\left (i \sin \left (2 e-\frac {2 c f}{d}\right )\right ) \int \frac {\cos \left (\frac {2 c f}{d}+2 f x\right )}{c+d x} \, dx}{2 a}+\frac {\sin \left (2 e-\frac {2 c f}{d}\right ) \int \frac {\sin \left (\frac {2 c f}{d}+2 f x\right )}{c+d x} \, dx}{2 a}\\ &=-\frac {\cos \left (2 e-\frac {2 c f}{d}\right ) \text {Ci}\left (\frac {2 c f}{d}+2 f x\right )}{2 a d}+\frac {\log (c+d x)}{2 a d}-\frac {i \text {Ci}\left (\frac {2 c f}{d}+2 f x\right ) \sin \left (2 e-\frac {2 c f}{d}\right )}{2 a d}-\frac {i \cos \left (2 e-\frac {2 c f}{d}\right ) \text {Si}\left (\frac {2 c f}{d}+2 f x\right )}{2 a d}+\frac {\sin \left (2 e-\frac {2 c f}{d}\right ) \text {Si}\left (\frac {2 c f}{d}+2 f x\right )}{2 a d}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.28, size = 77, normalized size = 0.48 \[ \frac {\log (c+d x)-\left (\text {Ci}\left (\frac {2 f (c+d x)}{d}\right )+i \text {Si}\left (\frac {2 f (c+d x)}{d}\right )\right ) \left (\cos \left (2 e-\frac {2 c f}{d}\right )+i \sin \left (2 e-\frac {2 c f}{d}\right )\right )}{2 a d} \]

Antiderivative was successfully verified.

[In]

Integrate[1/((c + d*x)*(a + I*a*Cot[e + f*x])),x]

[Out]

(Log[c + d*x] - (Cos[2*e - (2*c*f)/d] + I*Sin[2*e - (2*c*f)/d])*(CosIntegral[(2*f*(c + d*x))/d] + I*SinIntegra
l[(2*f*(c + d*x))/d]))/(2*a*d)

________________________________________________________________________________________

fricas [A]  time = 0.57, size = 51, normalized size = 0.32 \[ -\frac {{\rm Ei}\left (\frac {2 i \, d f x + 2 i \, c f}{d}\right ) e^{\left (\frac {2 i \, d e - 2 i \, c f}{d}\right )} - \log \left (\frac {d x + c}{d}\right )}{2 \, a d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(d*x+c)/(a+I*a*cot(f*x+e)),x, algorithm="fricas")

[Out]

-1/2*(Ei((2*I*d*f*x + 2*I*c*f)/d)*e^((2*I*d*e - 2*I*c*f)/d) - log((d*x + c)/d))/(a*d)

________________________________________________________________________________________

giac [B]  time = 0.55, size = 367, normalized size = 2.28 \[ -\frac {\cos \left (\frac {2 \, c f}{d}\right ) \cos \relax (e)^{2} \operatorname {Ci}\left (\frac {2 \, {\left (d f x + c f\right )}}{d}\right ) - i \, \cos \relax (e)^{2} \operatorname {Ci}\left (\frac {2 \, {\left (d f x + c f\right )}}{d}\right ) \sin \left (\frac {2 \, c f}{d}\right ) + 2 i \, \cos \left (\frac {2 \, c f}{d}\right ) \cos \relax (e) \operatorname {Ci}\left (\frac {2 \, {\left (d f x + c f\right )}}{d}\right ) \sin \relax (e) + 2 \, \cos \relax (e) \operatorname {Ci}\left (\frac {2 \, {\left (d f x + c f\right )}}{d}\right ) \sin \left (\frac {2 \, c f}{d}\right ) \sin \relax (e) - \cos \left (\frac {2 \, c f}{d}\right ) \operatorname {Ci}\left (\frac {2 \, {\left (d f x + c f\right )}}{d}\right ) \sin \relax (e)^{2} + i \, \operatorname {Ci}\left (\frac {2 \, {\left (d f x + c f\right )}}{d}\right ) \sin \left (\frac {2 \, c f}{d}\right ) \sin \relax (e)^{2} + i \, \cos \left (\frac {2 \, c f}{d}\right ) \cos \relax (e)^{2} \operatorname {Si}\left (\frac {2 \, {\left (d f x + c f\right )}}{d}\right ) + \cos \relax (e)^{2} \sin \left (\frac {2 \, c f}{d}\right ) \operatorname {Si}\left (\frac {2 \, {\left (d f x + c f\right )}}{d}\right ) - 2 \, \cos \left (\frac {2 \, c f}{d}\right ) \cos \relax (e) \sin \relax (e) \operatorname {Si}\left (\frac {2 \, {\left (d f x + c f\right )}}{d}\right ) + 2 i \, \cos \relax (e) \sin \left (\frac {2 \, c f}{d}\right ) \sin \relax (e) \operatorname {Si}\left (\frac {2 \, {\left (d f x + c f\right )}}{d}\right ) - i \, \cos \left (\frac {2 \, c f}{d}\right ) \sin \relax (e)^{2} \operatorname {Si}\left (\frac {2 \, {\left (d f x + c f\right )}}{d}\right ) - \sin \left (\frac {2 \, c f}{d}\right ) \sin \relax (e)^{2} \operatorname {Si}\left (\frac {2 \, {\left (d f x + c f\right )}}{d}\right ) - \log \left (d x + c\right )}{2 \, a d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(d*x+c)/(a+I*a*cot(f*x+e)),x, algorithm="giac")

[Out]

-1/2*(cos(2*c*f/d)*cos(e)^2*cos_integral(2*(d*f*x + c*f)/d) - I*cos(e)^2*cos_integral(2*(d*f*x + c*f)/d)*sin(2
*c*f/d) + 2*I*cos(2*c*f/d)*cos(e)*cos_integral(2*(d*f*x + c*f)/d)*sin(e) + 2*cos(e)*cos_integral(2*(d*f*x + c*
f)/d)*sin(2*c*f/d)*sin(e) - cos(2*c*f/d)*cos_integral(2*(d*f*x + c*f)/d)*sin(e)^2 + I*cos_integral(2*(d*f*x +
c*f)/d)*sin(2*c*f/d)*sin(e)^2 + I*cos(2*c*f/d)*cos(e)^2*sin_integral(2*(d*f*x + c*f)/d) + cos(e)^2*sin(2*c*f/d
)*sin_integral(2*(d*f*x + c*f)/d) - 2*cos(2*c*f/d)*cos(e)*sin(e)*sin_integral(2*(d*f*x + c*f)/d) + 2*I*cos(e)*
sin(2*c*f/d)*sin(e)*sin_integral(2*(d*f*x + c*f)/d) - I*cos(2*c*f/d)*sin(e)^2*sin_integral(2*(d*f*x + c*f)/d)
- sin(2*c*f/d)*sin(e)^2*sin_integral(2*(d*f*x + c*f)/d) - log(d*x + c))/(a*d)

________________________________________________________________________________________

maple [A]  time = 0.60, size = 204, normalized size = 1.27 \[ \frac {\ln \left (\left (f x +e \right ) d +c f -d e \right )}{2 a d}-\frac {\Si \left (2 f x +2 e +\frac {2 c f -2 d e}{d}\right ) \sin \left (\frac {2 c f -2 d e}{d}\right )}{2 a d}-\frac {\Ci \left (2 f x +2 e +\frac {2 c f -2 d e}{d}\right ) \cos \left (\frac {2 c f -2 d e}{d}\right )}{2 a d}-\frac {i \Si \left (2 f x +2 e +\frac {2 c f -2 d e}{d}\right ) \cos \left (\frac {2 c f -2 d e}{d}\right )}{2 a d}+\frac {i \Ci \left (2 f x +2 e +\frac {2 c f -2 d e}{d}\right ) \sin \left (\frac {2 c f -2 d e}{d}\right )}{2 a d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(d*x+c)/(a+I*a*cot(f*x+e)),x)

[Out]

1/2/a*ln((f*x+e)*d+c*f-d*e)/d-1/2/a*Si(2*f*x+2*e+2*(c*f-d*e)/d)*sin(2*(c*f-d*e)/d)/d-1/2/a*Ci(2*f*x+2*e+2*(c*f
-d*e)/d)*cos(2*(c*f-d*e)/d)/d-1/2*I/a*Si(2*f*x+2*e+2*(c*f-d*e)/d)*cos(2*(c*f-d*e)/d)/d+1/2*I/a*Ci(2*f*x+2*e+2*
(c*f-d*e)/d)*sin(2*(c*f-d*e)/d)/d

________________________________________________________________________________________

maxima [A]  time = 0.45, size = 111, normalized size = 0.69 \[ \frac {f \cos \left (-\frac {2 \, {\left (d e - c f\right )}}{d}\right ) E_{1}\left (-\frac {2 i \, {\left (f x + e\right )} d - 2 i \, d e + 2 i \, c f}{d}\right ) - i \, f E_{1}\left (-\frac {2 i \, {\left (f x + e\right )} d - 2 i \, d e + 2 i \, c f}{d}\right ) \sin \left (-\frac {2 \, {\left (d e - c f\right )}}{d}\right ) + f \log \left ({\left (f x + e\right )} d - d e + c f\right )}{2 \, a d f} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(d*x+c)/(a+I*a*cot(f*x+e)),x, algorithm="maxima")

[Out]

1/2*(f*cos(-2*(d*e - c*f)/d)*exp_integral_e(1, -(2*I*(f*x + e)*d - 2*I*d*e + 2*I*c*f)/d) - I*f*exp_integral_e(
1, -(2*I*(f*x + e)*d - 2*I*d*e + 2*I*c*f)/d)*sin(-2*(d*e - c*f)/d) + f*log((f*x + e)*d - d*e + c*f))/(a*d*f)

________________________________________________________________________________________

mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {1}{\left (a+a\,\mathrm {cot}\left (e+f\,x\right )\,1{}\mathrm {i}\right )\,\left (c+d\,x\right )} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((a + a*cot(e + f*x)*1i)*(c + d*x)),x)

[Out]

int(1/((a + a*cot(e + f*x)*1i)*(c + d*x)), x)

________________________________________________________________________________________

sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ - \frac {i \int \frac {1}{c \cot {\left (e + f x \right )} - i c + d x \cot {\left (e + f x \right )} - i d x}\, dx}{a} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(d*x+c)/(a+I*a*cot(f*x+e)),x)

[Out]

-I*Integral(1/(c*cot(e + f*x) - I*c + d*x*cot(e + f*x) - I*d*x), x)/a

________________________________________________________________________________________